来自 昏昏睡睡HSE · From Drowsy HSE
CSP DAILY LEARNING · DAY 81
本课只做一件事：用 5 道题检验「机械安全与安全防护装置」，并把错的那几道归到具体原因上。
Test Machine Safety & Safeguarding with five items and trace every miss to a specific cause.
本课不涉及：不出新知识点——只检验前四课学过的内容。
Not covered here: No new material — only what lessons 1 to 4 covered.
本课目标 | Learning objectives
- 5 题至少答对 4 题，并说清每题依据
- 把错题归为「词不懂 / 问句读错 / 依据不足」三类之一
- 说出本块学到的三条可迁移结论
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五题复盘 | Five-question recap
选出答案并提交，查看解析与依据。/ Pick an answer, submit, and read the rationale.
1. 安全距离公式 D = K × T + C 中，K 代表？
In D = K × T + C, what is K?
2. 光幕分辨率越粗（检测不到手指），侵入补偿 C 会？
The coarser the curtain resolution (fingers undetected), the compensation C becomes?
3. 频繁伸手进模具的工位，最合适的防护是？
For a station with frequent reaches into the die, the best safeguard is?
4. 制动监测器（brake monitor）的作用是？
What does a brake monitor do?
5. 联锁「跳接」的正确处理是？
The correct handling of an interlock jumper is?
错因归类 | Sort your misses
- 公式背成 D = K + T → 每次默写三要素（速度×时间+补偿）Mis-memorizing the formula as D = K + T → write out the three elements from memory each time (speed × time + compensation)
- 选型只看价格 → 按伸手频率与深度选型，再核安全距离Selecting on price alone → select by reach frequency and depth, then verify the safety distance
- 跳接无人管 → 建立旁路台账，审计必查Bypass jumps left unmanaged → keep a bypass ledger, checked in every audit
接下来学什么：下一块（Day 82–86）把块 12 的暴露控制四步落到第一种具体介质上：噪声与听力保护——从剂量公式到 NRR 衰减计算，从基线听力图到年报重评，Domain 1 与 Domain 6 在这里交棒。
Next block (Days 82–86) lands block 12's four steps on the first agent: noise and hearing conservation — dose formula to NRR attenuation, baseline audiograms to annual review, where Domain 1 hands over to Domain 6.
学习打卡与笔记 | Progress & notes
已完成 0/4 项 / 0/4 tasks complete
进度保存在当前浏览器，不会自动跨设备同步。/ Progress is stored in this browser only.
可靠来源 | Official references
BCSP — CSP Examination Blueprint (CSP11)
BCSP — Official Self-Assessments
BCSP — Certified Safety Professional (CSP)
Pearson VUE — CSP 考试预约 / Scheduling
本课为一般性学习资料，不替代现场专业评估、法规要求或组织程序。/ Educational content only.
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